Integrand size = 15, antiderivative size = 156 \[ \int \frac {1}{\left (a+b \sqrt {x}\right )^5 x^3} \, dx=\frac {b^4}{2 a^5 \left (a+b \sqrt {x}\right )^4}+\frac {10 b^4}{3 a^6 \left (a+b \sqrt {x}\right )^3}+\frac {15 b^4}{a^7 \left (a+b \sqrt {x}\right )^2}+\frac {70 b^4}{a^8 \left (a+b \sqrt {x}\right )}-\frac {1}{2 a^5 x^2}+\frac {10 b}{3 a^6 x^{3/2}}-\frac {15 b^2}{a^7 x}+\frac {70 b^3}{a^8 \sqrt {x}}-\frac {140 b^4 \log \left (a+b \sqrt {x}\right )}{a^9}+\frac {70 b^4 \log (x)}{a^9} \]
-1/2/a^5/x^2+10/3*b/a^6/x^(3/2)-15*b^2/a^7/x+70*b^4*ln(x)/a^9-140*b^4*ln(a +b*x^(1/2))/a^9+70*b^3/a^8/x^(1/2)+1/2*b^4/a^5/(a+b*x^(1/2))^4+10/3*b^4/a^ 6/(a+b*x^(1/2))^3+15*b^4/a^7/(a+b*x^(1/2))^2+70*b^4/a^8/(a+b*x^(1/2))
Time = 0.16 (sec) , antiderivative size = 128, normalized size of antiderivative = 0.82 \[ \int \frac {1}{\left (a+b \sqrt {x}\right )^5 x^3} \, dx=\frac {\frac {a \left (-3 a^7+8 a^6 b \sqrt {x}-28 a^5 b^2 x+168 a^4 b^3 x^{3/2}+1750 a^3 b^4 x^2+3640 a^2 b^5 x^{5/2}+2940 a b^6 x^3+840 b^7 x^{7/2}\right )}{\left (a+b \sqrt {x}\right )^4 x^2}-840 b^4 \log \left (a+b \sqrt {x}\right )+420 b^4 \log (x)}{6 a^9} \]
((a*(-3*a^7 + 8*a^6*b*Sqrt[x] - 28*a^5*b^2*x + 168*a^4*b^3*x^(3/2) + 1750* a^3*b^4*x^2 + 3640*a^2*b^5*x^(5/2) + 2940*a*b^6*x^3 + 840*b^7*x^(7/2)))/(( a + b*Sqrt[x])^4*x^2) - 840*b^4*Log[a + b*Sqrt[x]] + 420*b^4*Log[x])/(6*a^ 9)
Time = 0.31 (sec) , antiderivative size = 166, normalized size of antiderivative = 1.06, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {798, 54, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{x^3 \left (a+b \sqrt {x}\right )^5} \, dx\) |
\(\Big \downarrow \) 798 |
\(\displaystyle 2 \int \frac {1}{\left (a+b \sqrt {x}\right )^5 x^{5/2}}d\sqrt {x}\) |
\(\Big \downarrow \) 54 |
\(\displaystyle 2 \int \left (-\frac {70 b^5}{a^9 \left (a+b \sqrt {x}\right )}-\frac {35 b^5}{a^8 \left (a+b \sqrt {x}\right )^2}-\frac {15 b^5}{a^7 \left (a+b \sqrt {x}\right )^3}-\frac {5 b^5}{a^6 \left (a+b \sqrt {x}\right )^4}-\frac {b^5}{a^5 \left (a+b \sqrt {x}\right )^5}+\frac {70 b^4}{a^9 \sqrt {x}}-\frac {35 b^3}{a^8 x}+\frac {15 b^2}{a^7 x^{3/2}}-\frac {5 b}{a^6 x^2}+\frac {1}{a^5 x^{5/2}}\right )d\sqrt {x}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle 2 \left (-\frac {70 b^4 \log \left (a+b \sqrt {x}\right )}{a^9}+\frac {70 b^4 \log \left (\sqrt {x}\right )}{a^9}+\frac {35 b^4}{a^8 \left (a+b \sqrt {x}\right )}+\frac {35 b^3}{a^8 \sqrt {x}}+\frac {15 b^4}{2 a^7 \left (a+b \sqrt {x}\right )^2}-\frac {15 b^2}{2 a^7 x}+\frac {5 b^4}{3 a^6 \left (a+b \sqrt {x}\right )^3}+\frac {5 b}{3 a^6 x^{3/2}}+\frac {b^4}{4 a^5 \left (a+b \sqrt {x}\right )^4}-\frac {1}{4 a^5 x^2}\right )\) |
2*(b^4/(4*a^5*(a + b*Sqrt[x])^4) + (5*b^4)/(3*a^6*(a + b*Sqrt[x])^3) + (15 *b^4)/(2*a^7*(a + b*Sqrt[x])^2) + (35*b^4)/(a^8*(a + b*Sqrt[x])) - 1/(4*a^ 5*x^2) + (5*b)/(3*a^6*x^(3/2)) - (15*b^2)/(2*a^7*x) + (35*b^3)/(a^8*Sqrt[x ]) - (70*b^4*Log[a + b*Sqrt[x]])/a^9 + (70*b^4*Log[Sqrt[x]])/a^9)
3.23.22.3.1 Defintions of rubi rules used
Int[((a_) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[E xpandIntegrand[(a + b*x)^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && ILtQ[m, 0] && IntegerQ[n] && !(IGtQ[n, 0] && LtQ[m + n + 2, 0])
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[1/n Subst [Int[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]
Time = 3.59 (sec) , antiderivative size = 135, normalized size of antiderivative = 0.87
method | result | size |
derivativedivides | \(-\frac {1}{2 a^{5} x^{2}}+\frac {10 b}{3 a^{6} x^{\frac {3}{2}}}-\frac {15 b^{2}}{a^{7} x}+\frac {70 b^{4} \ln \left (x \right )}{a^{9}}-\frac {140 b^{4} \ln \left (a +b \sqrt {x}\right )}{a^{9}}+\frac {70 b^{3}}{a^{8} \sqrt {x}}+\frac {b^{4}}{2 a^{5} \left (a +b \sqrt {x}\right )^{4}}+\frac {10 b^{4}}{3 a^{6} \left (a +b \sqrt {x}\right )^{3}}+\frac {15 b^{4}}{a^{7} \left (a +b \sqrt {x}\right )^{2}}+\frac {70 b^{4}}{a^{8} \left (a +b \sqrt {x}\right )}\) | \(135\) |
default | \(-\frac {1}{2 a^{5} x^{2}}+\frac {10 b}{3 a^{6} x^{\frac {3}{2}}}-\frac {15 b^{2}}{a^{7} x}+\frac {70 b^{4} \ln \left (x \right )}{a^{9}}-\frac {140 b^{4} \ln \left (a +b \sqrt {x}\right )}{a^{9}}+\frac {70 b^{3}}{a^{8} \sqrt {x}}+\frac {b^{4}}{2 a^{5} \left (a +b \sqrt {x}\right )^{4}}+\frac {10 b^{4}}{3 a^{6} \left (a +b \sqrt {x}\right )^{3}}+\frac {15 b^{4}}{a^{7} \left (a +b \sqrt {x}\right )^{2}}+\frac {70 b^{4}}{a^{8} \left (a +b \sqrt {x}\right )}\) | \(135\) |
-1/2/a^5/x^2+10/3*b/a^6/x^(3/2)-15*b^2/a^7/x+70*b^4*ln(x)/a^9-140*b^4*ln(a +b*x^(1/2))/a^9+70*b^3/a^8/x^(1/2)+1/2*b^4/a^5/(a+b*x^(1/2))^4+10/3*b^4/a^ 6/(a+b*x^(1/2))^3+15*b^4/a^7/(a+b*x^(1/2))^2+70*b^4/a^8/(a+b*x^(1/2))
Leaf count of result is larger than twice the leaf count of optimal. 295 vs. \(2 (134) = 268\).
Time = 0.27 (sec) , antiderivative size = 295, normalized size of antiderivative = 1.89 \[ \int \frac {1}{\left (a+b \sqrt {x}\right )^5 x^3} \, dx=-\frac {420 \, a^{2} b^{10} x^{5} - 1470 \, a^{4} b^{8} x^{4} + 1820 \, a^{6} b^{6} x^{3} - 875 \, a^{8} b^{4} x^{2} + 78 \, a^{10} b^{2} x + 3 \, a^{12} + 840 \, {\left (b^{12} x^{6} - 4 \, a^{2} b^{10} x^{5} + 6 \, a^{4} b^{8} x^{4} - 4 \, a^{6} b^{6} x^{3} + a^{8} b^{4} x^{2}\right )} \log \left (b \sqrt {x} + a\right ) - 840 \, {\left (b^{12} x^{6} - 4 \, a^{2} b^{10} x^{5} + 6 \, a^{4} b^{8} x^{4} - 4 \, a^{6} b^{6} x^{3} + a^{8} b^{4} x^{2}\right )} \log \left (\sqrt {x}\right ) - 4 \, {\left (210 \, a b^{11} x^{5} - 770 \, a^{3} b^{9} x^{4} + 1022 \, a^{5} b^{7} x^{3} - 558 \, a^{7} b^{5} x^{2} + 85 \, a^{9} b^{3} x + 5 \, a^{11} b\right )} \sqrt {x}}{6 \, {\left (a^{9} b^{8} x^{6} - 4 \, a^{11} b^{6} x^{5} + 6 \, a^{13} b^{4} x^{4} - 4 \, a^{15} b^{2} x^{3} + a^{17} x^{2}\right )}} \]
-1/6*(420*a^2*b^10*x^5 - 1470*a^4*b^8*x^4 + 1820*a^6*b^6*x^3 - 875*a^8*b^4 *x^2 + 78*a^10*b^2*x + 3*a^12 + 840*(b^12*x^6 - 4*a^2*b^10*x^5 + 6*a^4*b^8 *x^4 - 4*a^6*b^6*x^3 + a^8*b^4*x^2)*log(b*sqrt(x) + a) - 840*(b^12*x^6 - 4 *a^2*b^10*x^5 + 6*a^4*b^8*x^4 - 4*a^6*b^6*x^3 + a^8*b^4*x^2)*log(sqrt(x)) - 4*(210*a*b^11*x^5 - 770*a^3*b^9*x^4 + 1022*a^5*b^7*x^3 - 558*a^7*b^5*x^2 + 85*a^9*b^3*x + 5*a^11*b)*sqrt(x))/(a^9*b^8*x^6 - 4*a^11*b^6*x^5 + 6*a^1 3*b^4*x^4 - 4*a^15*b^2*x^3 + a^17*x^2)
Leaf count of result is larger than twice the leaf count of optimal. 1391 vs. \(2 (151) = 302\).
Time = 3.09 (sec) , antiderivative size = 1391, normalized size of antiderivative = 8.92 \[ \int \frac {1}{\left (a+b \sqrt {x}\right )^5 x^3} \, dx=\text {Too large to display} \]
Piecewise((zoo/x**(9/2), Eq(a, 0) & Eq(b, 0)), (-1/(2*a**5*x**2), Eq(b, 0) ), (-2/(9*b**5*x**(9/2)), Eq(a, 0)), (zoo/x**2, Eq(a, -b*sqrt(x))), (-3*a* *8*sqrt(x)/(6*a**13*x**(5/2) + 24*a**12*b*x**3 + 36*a**11*b**2*x**(7/2) + 24*a**10*b**3*x**4 + 6*a**9*b**4*x**(9/2)) + 8*a**7*b*x/(6*a**13*x**(5/2) + 24*a**12*b*x**3 + 36*a**11*b**2*x**(7/2) + 24*a**10*b**3*x**4 + 6*a**9*b **4*x**(9/2)) - 28*a**6*b**2*x**(3/2)/(6*a**13*x**(5/2) + 24*a**12*b*x**3 + 36*a**11*b**2*x**(7/2) + 24*a**10*b**3*x**4 + 6*a**9*b**4*x**(9/2)) + 16 8*a**5*b**3*x**2/(6*a**13*x**(5/2) + 24*a**12*b*x**3 + 36*a**11*b**2*x**(7 /2) + 24*a**10*b**3*x**4 + 6*a**9*b**4*x**(9/2)) + 420*a**4*b**4*x**(5/2)* log(x)/(6*a**13*x**(5/2) + 24*a**12*b*x**3 + 36*a**11*b**2*x**(7/2) + 24*a **10*b**3*x**4 + 6*a**9*b**4*x**(9/2)) - 840*a**4*b**4*x**(5/2)*log(a/b + sqrt(x))/(6*a**13*x**(5/2) + 24*a**12*b*x**3 + 36*a**11*b**2*x**(7/2) + 24 *a**10*b**3*x**4 + 6*a**9*b**4*x**(9/2)) + 1750*a**4*b**4*x**(5/2)/(6*a**1 3*x**(5/2) + 24*a**12*b*x**3 + 36*a**11*b**2*x**(7/2) + 24*a**10*b**3*x**4 + 6*a**9*b**4*x**(9/2)) + 1680*a**3*b**5*x**3*log(x)/(6*a**13*x**(5/2) + 24*a**12*b*x**3 + 36*a**11*b**2*x**(7/2) + 24*a**10*b**3*x**4 + 6*a**9*b** 4*x**(9/2)) - 3360*a**3*b**5*x**3*log(a/b + sqrt(x))/(6*a**13*x**(5/2) + 2 4*a**12*b*x**3 + 36*a**11*b**2*x**(7/2) + 24*a**10*b**3*x**4 + 6*a**9*b**4 *x**(9/2)) + 3640*a**3*b**5*x**3/(6*a**13*x**(5/2) + 24*a**12*b*x**3 + 36* a**11*b**2*x**(7/2) + 24*a**10*b**3*x**4 + 6*a**9*b**4*x**(9/2)) + 2520...
Time = 0.19 (sec) , antiderivative size = 154, normalized size of antiderivative = 0.99 \[ \int \frac {1}{\left (a+b \sqrt {x}\right )^5 x^3} \, dx=\frac {840 \, b^{7} x^{\frac {7}{2}} + 2940 \, a b^{6} x^{3} + 3640 \, a^{2} b^{5} x^{\frac {5}{2}} + 1750 \, a^{3} b^{4} x^{2} + 168 \, a^{4} b^{3} x^{\frac {3}{2}} - 28 \, a^{5} b^{2} x + 8 \, a^{6} b \sqrt {x} - 3 \, a^{7}}{6 \, {\left (a^{8} b^{4} x^{4} + 4 \, a^{9} b^{3} x^{\frac {7}{2}} + 6 \, a^{10} b^{2} x^{3} + 4 \, a^{11} b x^{\frac {5}{2}} + a^{12} x^{2}\right )}} - \frac {140 \, b^{4} \log \left (b \sqrt {x} + a\right )}{a^{9}} + \frac {70 \, b^{4} \log \left (x\right )}{a^{9}} \]
1/6*(840*b^7*x^(7/2) + 2940*a*b^6*x^3 + 3640*a^2*b^5*x^(5/2) + 1750*a^3*b^ 4*x^2 + 168*a^4*b^3*x^(3/2) - 28*a^5*b^2*x + 8*a^6*b*sqrt(x) - 3*a^7)/(a^8 *b^4*x^4 + 4*a^9*b^3*x^(7/2) + 6*a^10*b^2*x^3 + 4*a^11*b*x^(5/2) + a^12*x^ 2) - 140*b^4*log(b*sqrt(x) + a)/a^9 + 70*b^4*log(x)/a^9
Time = 0.30 (sec) , antiderivative size = 119, normalized size of antiderivative = 0.76 \[ \int \frac {1}{\left (a+b \sqrt {x}\right )^5 x^3} \, dx=-\frac {140 \, b^{4} \log \left ({\left | b \sqrt {x} + a \right |}\right )}{a^{9}} + \frac {70 \, b^{4} \log \left ({\left | x \right |}\right )}{a^{9}} + \frac {840 \, b^{7} x^{\frac {7}{2}} + 2940 \, a b^{6} x^{3} + 3640 \, a^{2} b^{5} x^{\frac {5}{2}} + 1750 \, a^{3} b^{4} x^{2} + 168 \, a^{4} b^{3} x^{\frac {3}{2}} - 28 \, a^{5} b^{2} x + 8 \, a^{6} b \sqrt {x} - 3 \, a^{7}}{6 \, {\left (b x + a \sqrt {x}\right )}^{4} a^{8}} \]
-140*b^4*log(abs(b*sqrt(x) + a))/a^9 + 70*b^4*log(abs(x))/a^9 + 1/6*(840*b ^7*x^(7/2) + 2940*a*b^6*x^3 + 3640*a^2*b^5*x^(5/2) + 1750*a^3*b^4*x^2 + 16 8*a^4*b^3*x^(3/2) - 28*a^5*b^2*x + 8*a^6*b*sqrt(x) - 3*a^7)/((b*x + a*sqrt (x))^4*a^8)
Time = 5.78 (sec) , antiderivative size = 147, normalized size of antiderivative = 0.94 \[ \int \frac {1}{\left (a+b \sqrt {x}\right )^5 x^3} \, dx=\frac {\frac {4\,b\,\sqrt {x}}{3\,a^2}-\frac {1}{2\,a}-\frac {14\,b^2\,x}{3\,a^3}+\frac {875\,b^4\,x^2}{3\,a^5}+\frac {28\,b^3\,x^{3/2}}{a^4}+\frac {490\,b^6\,x^3}{a^7}+\frac {1820\,b^5\,x^{5/2}}{3\,a^6}+\frac {140\,b^7\,x^{7/2}}{a^8}}{a^4\,x^2+b^4\,x^4+4\,a^3\,b\,x^{5/2}+4\,a\,b^3\,x^{7/2}+6\,a^2\,b^2\,x^3}-\frac {280\,b^4\,\mathrm {atanh}\left (\frac {2\,b\,\sqrt {x}}{a}+1\right )}{a^9} \]